Which of the following solubility orders is c | vedclass

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Question

(D) The solubility of alkaline earth metal sulfates $(MSO_4)$ decreases down the group because the hydration enthalpy decreases more rapidly than the

Vedclass · Accepted Answer

$KOH > NaOH > LiOH$

Vedclass · Answer

(D) The solubility of alkaline earth metal sulfates $(MSO_4)$ decreases down the group because the hydration enthalpy decreases more rapidly than the lattice enthalpy as the size of the cation increases. Thus,the correct order is $MgSO_4 > CaSO_4 > SrSO_4 > BaSO_4$. For alkali metal hydroxides $(MOH)$,the solubility increases down the group due to the decrease in lattice energy being more significant than the decrease in hydration energy. Thus,the correct order is $LiOH Comparing the given options: Option $A$ is incorrect (it is the reverse of the actual trend). Option $B$ is incorrect (solubility of sulfides varies based on $K_{sp}$ values). Option $C$ is incorrect (solubility of carbonates increases down the group,but $Na_2CO_3$ is highly soluble). Option $D$ is correct: $KOH > NaOH > LiOH$.

Metals	Minerals
$1$. Lithium	$c$. Lepidolite
$2$. Barium	$a$. Witherite
$3$. Magnesium	$d$. Carnallite
$4$. Strontium	$b$. Celestine

Which of the following solubility orders is correct?

Similar Questions

Match the following:
Metals Minerals
$1$. Lithium $c$. Lepidolite
$2$. Barium $a$. Witherite
$3$. Magnesium $d$. Carnallite
$4$. Strontium $b$. Celestine

Nitrates of all metals are:

How does the ionization energy of Group $1$ elements change down the group?

Statement $A$: Extraction of magnesium is done by the electrolysis of a molten mixture of $MgCl_2$,$NaCl$,and $CaCl_2$.
Reason $R$: Calcium chloride acts as a reducing agent.

Which of the following ions forms a highly soluble hydroxide in water?

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