Which statement about the following equilibri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The equilibrium reaction is: $(CH_3)_3CO^- + H_2O \rightleftharpoons (CH_3)_3COH + OH^-$.Acid-base reactions always proceed in the direction of fo

Vedclass · Accepted Answer

The equilibrium favours the products.

Vedclass · Answer

(A) The equilibrium reaction is: $(CH_3)_3CO^- + H_2O \rightleftharpoons (CH_3)_3COH + OH^-$.Acid-base reactions always proceed in the direction of forming the weaker acid and the weaker base.Comparing the $pK_a$ values: $H_2O$ $(pK_a = 15.7)$ is a stronger acid than $(CH_3)_3COH$ $(pK_a = 18)$.Since the reaction proceeds from the stronger acid to the weaker acid,the equilibrium lies to the right (towards the products).Therefore,$(CH_3)_3CO^-$ is a stronger base than $OH^-$,and the equilibrium favours the formation of the weaker base $(OH^-)$ and the weaker acid $((CH_3)_3COH)$.Thus,$t$-butoxide is the dominant anionic species is incorrect,and the equilibrium favours the products.

Which statement about the following equilibrium is true?
$(CH_3)_3CO^-K^+ + H_2O \rightleftharpoons (CH_3)_3COH + K^+OH^-$
Given: $pK_a(H_2O) = 15.7$,$pK_a((CH_3)_3COH) = 18$

Similar Questions

Which species acts as an acid in the reaction $CH_{3}COOH_{(aq)} + H_{2}O_{(l)} \rightleftharpoons H_{3}O^{+}_{(aq)} + CH_{3}COO^{-}_{(aq)}$?

The conjugate bases for $HCO_3^-$ and $NH_3$,respectively,are

Which of the following is the weakest Bronsted base?

Which is the strongest of the following acids?

Derive the equation $K_a \times K_b = K_w$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which statement about the following equilibrium is true?$(CH_3)_3CO^-K^+ + H_2O \rightleftharpoons (CH_3)_3COH + K^+OH^-$Given: $pK_a(H_2O) = 15.7$,$pK_a((CH_3)_3COH) = 18$