Which statement is correct regarding the atom | vedclass

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(D) . Potassium $(K)$ is a metal that loses an electron to form a cation $(K^{+})$. The removal of an electron decreases the electron-electron repulsi

Vedclass · Accepted Answer

For potassium,the atomic radius $>$ ionic radius but for bromine,the atomic radius $ < $ ionic radius

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(D) . Potassium $(K)$ is a metal that loses an electron to form a cation $(K^{+})$. The removal of an electron decreases the electron-electron repulsion and increases the effective nuclear charge,resulting in an ionic radius that is smaller than the atomic radius $(K > K^{+})$. Bromine $(Br)$ is a non-metal that gains an electron to form an anion $(Br^{-})$. The addition of an electron increases the electron-electron repulsion,resulting in an ionic radius that is larger than the atomic radius $(Br < Br^{-})$. Therefore,for potassium,the atomic radius $>$ ionic radius,and for bromine,the atomic radius $ < $ ionic radius.

Which statement is correct regarding the atomic and ionic radii of potassium $(K)$ and bromine $(Br)$?

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