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(B) According to Newton's second law of motion,the force $F$ is given by the product of mass $m$ and acceleration $a$,i.e.,$F = m 	imes a$.For the fi

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Accelerating a $5 \ kg$ mass at $3 \ m s^{-2}$

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(B) According to Newton's second law of motion,the force $F$ is given by the product of mass $m$ and acceleration $a$,i.e.,$F = m 	imes a$.For the first case:Mass $m_1 = 2 \ kg$,Acceleration $a_1 = 5 \ m s^{-2}$Force $F_1 = 2 \ kg 	imes 5 \ m s^{-2} = 10 \ N$.For the second case:Mass $m_2 = 5 \ kg$,Acceleration $a_2 = 3 \ m s^{-2}$Force $F_2 = 5 \ kg 	imes 3 \ m s^{-2} = 15 \ N$.Comparing the two forces,$15 \ N > 10 \ N$.Therefore,accelerating a $5 \ kg$ mass at $3 \ m s^{-2}$ requires a greater force.

Which would require a greater force $-$ accelerating a $2 \ kg$ mass at $5 \ m s^{-2}$ or a $5 \ kg$ mass at $3 \ m s^{-2}$?

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