While a capacitor remains connected to a battery and a dielectric slab is inserted between the plates,then:
- APotential difference between the plates is changed
- BCharge flows from the battery to the capacitor
- CElectric field between the plates increases
- DEnergy stored in the capacitor decreases
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Explain the effect of a dielectric on the capacitance of a parallel plate capacitor and obtain the formula for the dielectric constant.
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View Solution$A$ charged conductor produces an electric field of intensity $10^3 \ V/m$ just outside its surface in vacuum. Then,it produces an electric field of intensity $E$ just outside its surface,when it is placed in a medium of dielectric constant $4$. The value of $E$ will be (in $V/m$)
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