While a collector to emitter voltage is constant in a transistor,the collector current changes by $8.2 \, mA$ when the emitter current changes by $8.3 \, mA$. The value of forward current gain $h_{fe}$ is

In a common emitter transistor amplifier,the resistance of the collector is $3 \ k\Omega$. If the current amplification factor is $100$ and the base resistance is $2 \ k\Omega$,then the power gain of the transistor is:

In a common emitter amplifier,a change of $0.2 \text{ mA}$ in the base current causes a change of $5 \text{ mA}$ in the collector current. If the input resistance is $2 \text{ k}\Omega$ and the voltage gain is $75$,what is the load resistance used in the circuit?

Consider an $NPN$ transistor amplifier in common-emitter configuration. The current gain of the transistor is $100$. If the collector current changes by $1\, mA$,what will be the change in emitter current in $mA$?

In a $p-n-p$ transistor, the current carriers are

For the given bipolar junction transistor,find the approximate value of $I_B$,if $V_{CC} = 9 \ V$,$V_{BB} = 1.5 \ V$,$R_C = 13 \ k\Omega$,$R_E = 17 \ k\Omega$,and $\beta = 100$. (Assume the transistor is in active mode and $V_{BE} = 0.7 \ V$)