Why do compounds having similar geometry have different magnetic moments?
(N/A) The difference in magnetic moment arises due to the presence of weak field and strong field ligands.
If a ligand is strong,the complex formed will be of low spin,and if a ligand is weak,the complex formed is of high spin.
For example,$[CoF_{6}]^{3-}$ is paramagnetic while $[Co(NH_{3})_{6}]^{3+}$ is diamagnetic.
If a ligand is strong,the complex formed will be of low spin,and if a ligand is weak,the complex formed is of high spin.
For example,$[CoF_{6}]^{3-}$ is paramagnetic while $[Co(NH_{3})_{6}]^{3+}$ is diamagnetic.
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Similar Questions
$[Fe(CN)_6]^{4-}$; $[Fe(CN)_6]^{3-}$; $[Ti(CN)_6]^{3-}$; $[Ni(CN)_4]^{2-}$; $[Co(CN)_6]^{3-}$
Among the given complexes,the number of paramagnetic complexes is .... .
Among the given complexes,the number of paramagnetic complexes is .... .
Match the column:
Column-$I$ Column-$II$ $(a) [Pt(NH_3)_3Cl]Br$ $(P) \text{Coordination isomerism}$ $(b) [Cr(NH_3)_5(NCS)]^{+2}$ $(Q) \text{Ionisation isomerism}$ $(c) [Co(H_2O)_6]Cl_3$ $(R) \text{Linkage isomerism}$ $(d) [PtCl_4][Pt(NH_3)_4]$ $(S) \text{Hydrate isomerism}$
| Column-$I$ | Column-$II$ |
|---|---|
| $(a) [Pt(NH_3)_3Cl]Br$ | $(P) \text{Coordination isomerism}$ |
| $(b) [Cr(NH_3)_5(NCS)]^{+2}$ | $(Q) \text{Ionisation isomerism}$ |
| $(c) [Co(H_2O)_6]Cl_3$ | $(R) \text{Linkage isomerism}$ |
| $(d) [PtCl_4][Pt(NH_3)_4]$ | $(S) \text{Hydrate isomerism}$ |
Medium
View SolutionComplex $X$ of composition $Cr(H_{2}O)_{6}Cl_{n}$ has a spin-only magnetic moment of $3.83 \ BM$. It reacts with $AgNO_{3}$ and shows geometrical isomerism. The $IUPAC$ nomenclature of $X$ is
The calculated magnetic moment value for the $Fe^{2+}$ ion in $BM$ is:
Which of the following complexes is paramagnetic?
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