Why does the compound $(A)$ given below not form an oxime?

(N/A) The formation of an oxime requires a free carbonyl group (aldehyde or ketone) to react with hydroxylamine $(NH_2OH)$.
In the given structure,the glucose derivative is in its cyclic hemiacetal form where the anomeric carbon is involved in the ring structure.
Furthermore,the hydroxyl groups are acetylated $(OAc)$.
Since there is no free aldehyde or ketone group available in the cyclic structure,it cannot react with hydroxylamine to form an oxime.