Why does the rate of a reaction increase with a rise in temperature?

  • A
    The number of collisions increases.
  • B
    The activation energy decreases.
  • C
    $A$ larger fraction of molecules possess energy greater than the activation energy.
  • D
    The frequency of effective collisions increases due to higher kinetic energy.

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$A$ reaction takes place in three steps with individual rate constant and activation energy,
Step Rate constant and Activation energy
$Step \ 1$ $k_1, E_{a_1} = 180 \ kJ \ mol^{-1}$
$Step \ 2$ $k_2, E_{a_2} = 80 \ kJ \ mol^{-1}$
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Overall rate constant,$k = (k_1 k_2 / k_3)^{2/3}$. The overall activation energy of the reaction will be ........ $kJ \ mol^{-1}$.

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For a first-order gaseous reaction,a plot of $\log \, k$ versus $1/T$ gives a straight line with a slope of $-8000$. Calculate the activation energy $(E_a)$ of the reaction in $cal$.

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