Why is the alkyl halide shown below not capable of undergoing an $E2$ reaction upon treatment with sodium ethoxide?

  • A
    $Br^-$ is a too poor leaving group.
  • B
    Too much angle strain would be present in the alkene product.
  • C
    Sodium ethoxide is a poor base to use in $E2$ reaction.
  • D
    The $C-H$ and $C-Br$ bonds which need to break cannot achieve an anti-periplanar orientation.

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