Why is the diffraction of sound waves more evident in daily experience than that of light waves?

(A) The condition for significant diffraction is that the size of the obstacle or aperture $(d)$ must be comparable to the wavelength $(\lambda)$ of the wave, i.e., $\frac{\lambda}{d} \approx 1$.
For visible light, the wavelength $\lambda$ is approximately $6 \times 10^{-7} \,m$. Since most obstacles in our daily life are much larger than this (e.g., $d \approx 10^{-1} \,m$ to $1 \,m$), the ratio $\frac{\lambda}{d}$ is extremely small, making diffraction negligible.
For sound waves, the audible frequency range is $20 \,Hz$ to $20,000 \,Hz$. Taking a typical frequency of $332 \,Hz$ and the speed of sound $v = 332 \,m/s$, the wavelength is $\lambda = \frac{v}{f} = \frac{332}{332} = 1 \,m$.
Since the wavelength of sound $(1 \,m)$ is comparable to the size of common obstacles like doors or windows, the ratio $\frac{\lambda}{d}$ is significant, leading to prominent diffraction.
Therefore, we can hear sounds around corners or through doorways, but we cannot see light around them.