Why is the probability of a reaction with mol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Molecularity is defined as the number of reacting species (atoms,ions,or molecules) taking part in an elementary reaction,which must collide simul

Vedclass · Accepted Answer

Because the simultaneous collision of more than $3$ molecules is statistically very unlikely.

Vedclass · Answer

(B) Molecularity is defined as the number of reacting species (atoms,ions,or molecules) taking part in an elementary reaction,which must collide simultaneously in order to bring about a chemical reaction.For a reaction to occur,these species must collide effectively.The probability of more than $3$ molecules colliding simultaneously is extremely low because it requires a precise orientation and energy alignment for all particles at the same instant.Therefore,reactions with molecularity greater than $3$ are very rare.

Why is the probability of a reaction with molecularity higher than $3$ very rare?

Similar Questions

When the initial concentration of a reactant is doubled in a reaction,its half-life period is not affected. The order of the reaction is:

The half-life for a second-order reaction is $30 \ min$. If the initial concentration is $0.1 \ M$,then the value of the rate constant will be $............ \ M^{-1} \ min^{-1}$.

The rate constant of the reaction,$2 H_2O_2 \rightarrow 2 H_2O + O_2$ is $3 \times 10^{-3} \ min^{-1}$. At what concentration of $H_2O_2$ will the rate of reaction be $2 \times 10^{-4} \ M \ s^{-1}$?

The rate law for the reaction $A + B \rightarrow C$ at $25^{\circ} C$ is given by $\text{rate} = k[A][B]^2$. Calculate the rate of reaction if the rate constant at the same temperature is $6.25 \ mol^{-2} \ dm^6 \ s^{-1}$ where $[A] = 1 \ M$ and $[B] = 0.2 \ M$.

The rate law for the reaction $RCl + NaOH_{(aq)} \to ROH + NaCl$ is given by $\text{Rate} = K_1[RCl]$. The rate of the reaction will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module