Why is the value of g more at the poles than | vedclass

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(B) The acceleration due to gravity is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the gravitational constant,$M$ is the mass of the Earth,

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The Earth is flattened at the poles and bulges at the equator.

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(B) The acceleration due to gravity is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the gravitational constant,$M$ is the mass of the Earth,and $R$ is the distance from the center of the Earth.Since the Earth is not a perfect sphere but is flattened at the poles and bulges at the equator,the radius $R$ at the poles is less than the radius $R$ at the equator.Because $g$ is inversely proportional to the square of the radius $(g \propto \frac{1}{R^2})$,a smaller radius at the poles results in a higher value of $g$ compared to the equator.

Why is the value of $g$ more at the poles than at the equator?

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