With respect to air,the critical angle in a m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The critical angle $C$ is given by the formula $C = \sin^{-1}\left(\frac{1}{\mu}ight)$.For red light,$	heta = \sin^{-1}\left(\frac{1}{\mu_{\lam

Vedclass · Accepted Answer

Less than $	heta$

Vedclass · Answer

(C) The critical angle $C$ is given by the formula $C = \sin^{-1}\left(\frac{1}{\mu}ight)$.For red light,$	heta = \sin^{-1}\left(\frac{1}{\mu_{\lambda_1}}ight)$,and for yellow light,$	heta' = \sin^{-1}\left(\frac{1}{\mu_{\lambda_2}}ight)$.According to Cauchy's dispersion formula,the refractive index $\mu$ is inversely related to the wavelength $\lambda$. Since the wavelength of yellow light is less than the wavelength of red light $(\lambda_2  \mu_{\lambda_1})$.Since $\mu_{\lambda_2} > \mu_{\lambda_1}$,it follows that $\frac{1}{\mu_{\lambda_2}} Therefore,$	heta' < 	heta$. Thus,the critical angle for yellow light will be less than $	heta$.

With respect to air,the critical angle in a medium for light of red colour $[{\lambda _1}]$ is $\theta$. Other factors remaining the same,the critical angle for light of yellow colour $[{\lambda _2}]$ will be:

Similar Questions

White light is incident on the interface of glass and air as shown in the figure. If green light is just totally internally reflected,then the reflected rays inside the glass contain:

$A$ light ray falls on a square glass slab as shown in the diagram. The index of refraction of the glass,if total internal reflection is to occur at the vertical face,is equal to

Light travels in two media $A$ and $B$ with speeds $1.8 \times 10^8 \ m/s$ and $2.4 \times 10^8 \ m/s$ respectively. Then the critical angle between them is

One of the necessary conditions for total internal reflection to take place is ($i =$ angle of incidence,$i_{c} =$ critical angle).

Three transparent media of refractive indices $\mu_1, \mu_2, \mu_3$,respectively,are stacked as shown below. $A$ ray of light follows the path shown. No light enters the third medium. Then,

Vedclass Test Series

Exam Paper Generator

Online Exam Module