With respect to the roots of x^{2}-x-2=0,we c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given quadratic equation is $x^{2}-x-2=0$.To find the roots,we factorize the equation:$x^{2}-2x+x-2=0$$x(x-2)+1(x-2)=0$$(x-2)(x+1)=0$Thus,the

Vedclass · Accepted Answer

both of them are integers

Vedclass · Answer

(B) The given quadratic equation is $x^{2}-x-2=0$.To find the roots,we factorize the equation:$x^{2}-2x+x-2=0$$x(x-2)+1(x-2)=0$$(x-2)(x+1)=0$Thus,the roots are $x=2$ and $x=-1$.Since both $2$ and $-1$ are integers,option $B$ is correct.Also,note that one root is positive and one is negative,so option $C$ is partially true but $B$ is a more comprehensive description of the nature of the roots.

With respect to the roots of $x^{2}-x-2=0$,we can say that

Similar Questions

The roots of the equation $a(x^2 + 1) - (a^2 + 1)x = 0$ are

Find two consecutive positive odd integers whose squares have the sum $290.$

If the roots of $4x^2 + px + 9 = 0$ are equal,then the absolute value of $p$ is:

If $\alpha$ and $\beta$ are the roots of the equation $x^2 + 6x + \lambda = 0$ and $3\alpha + 2\beta = -20$,then $\lambda = $

The complete solution set of the inequality $(\sec^{-1}x - 4)(\sec^{-1}x - 1)(\sec^{-1}x - 2) \ge 0$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module