(B) The sensitivity of a potentiometer is defined as the smallest potential difference that can be measured by it.The potential gradient $(k)$ is defi

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(B) The sensitivity of a potentiometer is defined as the smallest potential difference that can be measured by it.The potential gradient $(k)$ is defined as the potential drop per unit length of the wire,given by $k = V/L$.Sensitivity is inversely proportional to the potential gradient $(k)$. Therefore,as $k$ decreases,the sensitivity increases.Since $k = V/L$,decreasing $k$ is equivalent to increasing the length $(L)$ of the potentiometer wire for a fixed potential difference $(V)$.Thus,sensitivity is directly proportional to the length $(L)$ of the wire and inversely proportional to the potential gradient $(k)$.Statements $(A)$ and $(C)$ are correct.

Class 12 Physics Current Electricity Potentiometer

Medium

With the help of a potentiometer,we can determine the value of the emf of a given cell. The sensitivity of the potentiometer is:
$(A)$ directly proportional to the length of the potentiometer wire
$(B)$ directly proportional to the potential gradient of the wire
$(C)$ inversely proportional to the potential gradient of the wire
$(D)$ inversely proportional to the length of the potentiometer wire
Choose the correct option for the above statements:

JEE MAIN 2023 All JEE MAIN

A
$B$ and $D$ only
B
$A$ and $C$ only
C
$A$ only
D
$C$ only

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Current Electricity

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$A$ potentiometer wire is $100 \, cm$ long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at $50 \, cm$ and $10 \, cm$ from the positive end of the wire in the two cases. The ratio of emfs is:

MediumNEET 2016

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In the given arrangement,$E_1 = 5 \, V$ and $E_2 = 7 \, V$. The balancing length is $6 \, m$. If the terminals of $E_2$ are reversed,then the new balancing length will be:

Medium

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The given figure represents an arrangement of a potentiometer for the calculation of the internal resistance $(r)$ of an unknown battery $(E)$. The balance length is $70.0 \, cm$ with the key open and $60.0 \, cm$ with the key closed. $R$ is $132.40 \, \Omega$. The internal resistance $(r)$ of the unknown cell will be ....... $\Omega$ (Given $E_o > E$):-

Medium

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$A$ potentiometer wire has length $10\, m$ and resistance $10\, \Omega$. It is connected to a battery of $EMF$ $11\, V$ and internal resistance $1\, \Omega$. The potential gradient in the wire is ............... $V/m$.

Medium

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The length of a wire of a potentiometer is $100 \, cm$,and the $emf$ of its standard cell is $E \, volt$. It is employed to measure the $emf$ of a battery whose internal resistance is $0.5 \, \Omega$. If the balance point is obtained at $l = 30 \, cm$ from the positive end,the $emf$ of the battery is (where $i$ is the current in the potentiometer wire).

MediumAIEEE 2003

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In the given arrangement,$E_1 = 5 \, V$ and $E_2 = 7 \, V$. The balancing length is $6 \, m$. If the terminals of $E_2$ are reversed,then the new balancing length will be:

$A$ potentiometer wire has length $10\, m$ and resistance $10\, \Omega$. It is connected to a battery of $EMF$ $11\, V$ and internal resistance $1\, \Omega$. The potential gradient in the wire is ............... $V/m$.

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