Class 11MathematicsTrigonometrical EquationsRelation between sides and angles, Solutions of triangles
EasyWith usual notations in $\Delta ABC$,$a=3$,$c=2$ and $\sin C=\frac{2}{3}$,then $\angle A=$
- A$\frac{\pi}{4}$
- B$\frac{\pi}{3}$
- C$\frac{\pi}{2}$
- D$\frac{\pi}{6}$
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Similar Questions
In a $\Delta ABC,$ if $3a = b + c,$ then the value of $\cot \frac{B}{2} \cot \frac{C}{2}$ is
Medium
View SolutionIn a triangle $ABC$,with usual notations,if $a=4, b=8, \angle C=60^{\circ}$,then the value of $\angle B$ and the ratio $\cos A : \cos C$ respectively are,
In triangle $ABC$,if $A=\frac{\pi}{3}$ and $B=\frac{\pi}{4}$,then $\frac{a^2-b^2}{c^2}=$
If $b+c=3a$,then $\cot \frac{B}{2} \cot \frac{C}{2}$ is equal to :
DifficultAP EAMCET 2006
View SolutionIf $4$ times the area of a $\triangle ABC$ is $c^2-(a-b)^2$,then $\sin C$ is equal to:
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