(D) Using the Law of Cosines in $\triangle ABC$:\\ $\cos C = \frac{a^2+b^2-c^2}{2ab}$\\ Given that $a^2+b^2-c^2=ab$,we substitute this into the formul

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(D) Using the Law of Cosines in $\triangle ABC$:\\ $\cos C = \frac{a^2+b^2-c^2}{2ab}$\\ Given that $a^2+b^2-c^2=ab$,we substitute this into the formula:\\ $\cos C = \frac{ab}{2ab} = \frac{1}{2}$\\ Since $\cos C = \frac{1}{2}$,the angle $C$ is $\frac{\pi}{3}$ (or $60^{\circ}$).

Class 11 Mathematics Trigonometrical Equations Relation between sides and angles, Solutions of triangles

Medium

With usual notations in $\triangle ABC$,if $a^2+b^2-c^2=ab$,then the measure of angle $C$ is

MHT CET 2022 All MHT CET

A
$\frac{\pi}{4}$
B
$\frac{\pi}{6}$
C
$\frac{\pi}{2}$
D
$\frac{\pi}{3}$

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Class 11

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Trigonometrical Equations

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Relation between sides and angles, Solutions of triangles

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With usual notations in $\triangle ABC$,if $a^2+b^2-c^2=ab$,then the measure of angle $C$ is

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