With what velocity an observer should move re | vedclass

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(D) Applying Doppler's effect to sound waves,the observed frequency $n^{\prime}$ is given by $n^{\prime} = n \left( \frac{v + v_0}{v} \right) = n \lef

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Twice the velocity of sound towards the source.

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(D) Applying Doppler's effect to sound waves,the observed frequency $n^{\prime}$ is given by $n^{\prime} = n \left( \frac{v + v_0}{v} \right) = n \left( 1 + \frac{v_0}{v} \right)$,where $v$ is the velocity of sound and $v_0$ is the velocity of the observer moving towards the source.Given that the observed frequency is triple the source frequency,$n^{\prime} = 3n$.Substituting this into the equation: $3n = n \left( 1 + \frac{v_0}{v} \right)$.Dividing both sides by $n$: $3 = 1 + \frac{v_0}{v}$.Solving for $v_0$: $\frac{v_0}{v} = 2$,which implies $v_0 = 2v$.Therefore,the observer must move with twice the velocity of sound towards the source.

With what velocity an observer should move relative to a stationary source so that a sound of triple the frequency of source is heard by an observer?

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