Without actually calculating the cubes,find t | vedclass

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(C) Let $x = -12, y = 7,$ and $z = 5$.Then,$x + y + z = -12 + 7 + 5 = 0$.We know that if $x + y + z = 0$,then $x^{3} + y^{3} + z^{3} = 3xyz$.Therefore

Vedclass · Accepted Answer

$-1260$

Vedclass · Answer

(C) Let $x = -12, y = 7,$ and $z = 5$.Then,$x + y + z = -12 + 7 + 5 = 0$.We know that if $x + y + z = 0$,then $x^{3} + y^{3} + z^{3} = 3xyz$.Therefore,$(-12)^{3} + (7)^{3} + (5)^{3} = 3[(-12)(7)(5)]$,since $(-12) + 7 + 5 = 0$.Calculating the product: $3[-420] = -1260$.Thus,$(-12)^{3} + (7)^{3} + (5)^{3} = -1260$.

Without actually calculating the cubes,find the value of each of the following: $(-12)^{3} + (7)^{3} + (5)^{3}$

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