Work done by air when it expands from 50 , L | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The work done during an isobaric expansion is given by the formula $W = P \Delta V$.Given:Pressure $P = 2 \, atm = 2 	imes 1.013 	imes 10^5 \, P

Vedclass · Accepted Answer

$2 	imes 10^4 \, J$

Vedclass · Answer

(A) The work done during an isobaric expansion is given by the formula $W = P \Delta V$.Given:Pressure $P = 2 \, atm = 2 	imes 1.013 	imes 10^5 \, Pa \approx 2 	imes 10^5 \, Pa$.Initial volume $V_1 = 50 \, L = 50 	imes 10^{-3} \, m^3$.Final volume $V_2 = 150 \, L = 150 	imes 10^{-3} \, m^3$.Change in volume $\Delta V = V_2 - V_1 = (150 - 50) 	imes 10^{-3} \, m^3 = 100 	imes 10^{-3} \, m^3 = 0.1 \, m^3$.Substituting the values into the work formula:$W = (2 	imes 10^5 \, Pa) 	imes (0.1 \, m^3) = 2 	imes 10^4 \, J$.Thus,the correct option is $A$.

Work done by air when it expands from $50 \, L$ to $150 \, L$ at a constant pressure of $2 \, atm$ is:

Similar Questions

The condition $dQ = dU$ (heat supplied equals the increase in internal energy) is true for which of the following processes?

Two cylinders contain the same amount of an ideal monatomic gas. The same amount of heat is given to both cylinders. If the temperature rise in cylinder $A$ is $T_0$,then the temperature rise in cylinder $B$ will be:

Describe the nature of $P-V$ diagrams for isobaric and isochoric processes.

$A$ sample of gas expands from volume ${V_1}$ to ${V_2}$. The amount of work done by the gas is greatest when the expansion is

One mole of a diatomic gas is heated at constant pressure starting at $ 27^{\circ}C $. How much energy must be added to the gas as heat to double its volume?

Vedclass Test Series

Exam Paper Generator

Online Exam Module