Work done by a magnetic field of 1,T on a par | vedclass

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(C) The magnetic force $\vec{F}_m$ acting on a charged particle moving with velocity $\vec{v}$ in a magnetic field $\vec{B}$ is given by the Lorentz f

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(C) The magnetic force $\vec{F}_m$ acting on a charged particle moving with velocity $\vec{v}$ in a magnetic field $\vec{B}$ is given by the Lorentz force formula: $\vec{F}_m = q(\vec{v} 	imes \vec{B})$.Since the magnetic force is always perpendicular to the velocity vector $\vec{v}$,the instantaneous power delivered by the magnetic field is $P = \vec{F}_m \cdot \vec{v} = 0$.Because the power is zero at every instant,the total work done $W = \int P \, dt$ by the magnetic field on the charged particle is always $0\,J$,regardless of the speed,charge,or time duration.

Work done by a magnetic field of $1\,T$ on a particle of charge $1\,C$ moving with a speed of $5\,m/s$ in one second is........$J$.

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