Work done for the process shown in the figure is ............ $J$

In the following $p-V$ diagram, the equation of state along the curved path is given by $(V-2)^2 = 4aP$, where $a$ is a constant. The total work done in the closed path is:

An ideal monoatomic gas is taken round the cycle $12341$ shown in the figure ($p-V$ diagram). The work done in one cycle is (in $P_0V_0$)?

One mole of an ideal gas is taken from $a$ to $b$ along two paths denoted by the solid and the dashed lines as shown in the graph below. If the work done along the solid line path is $w_s$ and that along the dotted line path is $w_d$,then the integer closest to the ratio $w_d / w_s$ is

$A$ gas takes part in two processes in which it is heated from the same initial state $1$ to the same final temperature. The processes are shown on the $P-V$ diagram by the straight lines $1-2$ and $1-3$. Points $2$ and $3$ lie on the same isothermal curve. If $Q_1$ and $Q_2$ are the heat transferred along the two processes,then:

One mole of an ideal gas is taken from $A$ to $B$,from $B$ to $C$,and then back to $A$. The variation of its volume with temperature for that change is as shown. Its pressure at $A$ is $P_{0}$ and volume is $V_{0}$. Then,the internal energy: