Work done in the cyclic process shown in the | vedclass

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(C) The given $P-V$ graph represents a circle.For a cyclic process,the work done is equal to the area enclosed by the $P-V$ curve.Since the process is

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$-\frac{22}{7} P_0 V_0$

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(C) The given $P-V$ graph represents a circle.For a cyclic process,the work done is equal to the area enclosed by the $P-V$ curve.Since the process is anticlockwise,the work done is negative.The area of the circle is given by $A = \pi R_1 R_2$,where $R_1$ and $R_2$ are the semi-axes of the ellipse (or radii of the circle).From the graph,the diameter along the pressure axis is $3 P_0 - P_0 = 2 P_0$,so the semi-axis $R_1 = \frac{2 P_0}{2} = P_0$.The diameter along the volume axis is $3 V_0 - V_0 = 2 V_0$,so the semi-axis $R_2 = \frac{2 V_0}{2} = V_0$.Therefore,the work done $W = -(	ext{Area of the circle}) = -\pi R_1 R_2$.$W = -\pi (P_0) (V_0) = -\frac{22}{7} P_0 V_0$.

Work done in the cyclic process shown in the figure is ...........

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