Work done in time t on a body of mass m which | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The body starts from rest,so initial velocity $u = 0$.The acceleration $a$ is constant,given by $a = \frac{v - u}{t_1} = \frac{v}{t_1}$.The displa

Vedclass · Accepted Answer

$\frac{1}{2}m\frac{v^2}{t_1^2}t^2$

Vedclass · Answer

(D) The body starts from rest,so initial velocity $u = 0$.The acceleration $a$ is constant,given by $a = \frac{v - u}{t_1} = \frac{v}{t_1}$.The displacement $s$ at any time $t$ is given by $s = ut + \frac{1}{2}at^2 = 0 + \frac{1}{2}at^2 = \frac{1}{2}at^2$.The force applied is $F = ma = m\left( \frac{v}{t_1} ight)$.Work done $W = F 	imes s = \left( m \frac{v}{t_1} ight) 	imes \left( \frac{1}{2} \left( \frac{v}{t_1} ight) t^2 ight)$.$W = \frac{1}{2} m \frac{v^2}{t_1^2} t^2$.

Work done in time $t$ on a body of mass $m$ which is accelerated from rest to a speed $v$ in time $t_1$ as a function of time $t$ is given by:

Similar Questions

In an $FM$ system, a $7\, kHz$ signal modulates a $108\, MHz$ carrier such that the frequency deviation is $50\, kHz$. The carrier swing is: (in $ kHz$)

The area (in square units) of the triangle formed by the lines $x=0$,$y=0$ and $3x+4y=12$ is:

$A$ gramophone record is revolving with an angular velocity $\omega$. $A$ coin is placed at a distance $r$ from the centre of the record. The static coefficient of friction is $\mu$. The coin will revolve with the record if

To remove the second term of the equation $x^4-8x^3+x^2-x+3=0$,diminish the roots of the equation by

$Fe_2Cr_2O_4 + Na_2CO_3 + O_2$ $\xrightarrow{\text{Fusion}} [X]$ $\xrightarrow[H_2O]{H^+} [Y]$ $\xrightarrow{H_2O_2/H^+} [Z]$
Which of the following statements is true for the compounds $[X], [Y]$ and $[Z]$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module