(A) We use the formula: $\frac{M_{1} \times D_{1} \times t_{1}}{W_{1}} = \frac{M_{2} \times D_{2} \times t_{2}}{W_{2}}$Given:$M_{1} = 24, D_{1} = 27,

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(A) We use the formula: $\frac{M_{1} \times D_{1} \times t_{1}}{W_{1}} = \frac{M_{2} \times D_{2} \times t_{2}}{W_{2}}$Given:$M_{1} = 24, D_{1} = 27, t_{1} = 7, W_{1} = 1$$M_{2} = 14, D_{2} = ?, t_{2} = 9, W_{2} = 1$Substituting the values:$24 \times 27 \times 7 = 14 \times D_{2} \times 9$$D_{2} = \frac{24 \times 27 \times 7}{14 \times 9}$$D_{2} = \frac{24 \times 3 \times 7}{14}$$D_{2} = \frac{24 \times 3}{2} = 12 \times 3 = 36$Therefore,$14$ men will complete the work in $36$ $\text{days}$.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Medium

Working $7\, \text{hours}$ daily,$24$ men can complete a piece of work in $27$ $\text{days}$. In how many $\text{days}$ would $14$ men complete the same piece of work working $9\, \text{hours}$ daily?

A
$36$
B
$30$
C
$32$
D
None of these

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Time and Work and Wages

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Time and Work

$A$ can do a piece of work in $12$ days and $B$ in $20$ days. If they together work on it for $5$ days and the remaining work is completed by $C$ in $3$ days, then in how many days can $C$ do the same work alone?

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$A$ can do a work in $15 \text{ days}$ and $B$ in $20 \text{ days}$. If they work together on it for $4 \text{ days}$,then the fraction of the work that is left is

Medium

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$A$ and $B$ can complete a piece of work in $15$ days and $10$ days respectively. They contracted to complete the work for $Rs. 30000$. The share of $A$ in the contracted money will be (in $Rs.$)

Easy

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$A$ and $B$ can complete a piece of work in $45$ and $40$ days respectively. Both started to work together,but after some days $A$ left and $B$ alone completed the remaining work in $23$ days. For how many days did $A$ work?

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$10$ men working $6\, \text{h}$ a day can complete a work in $18\, \text{days}$. How many $\text{hours per day}$ must $15$ men work to complete the same work in $12\, \text{days}$?

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Working $7\, \text{hours}$ daily,$24$ men can complete a piece of work in $27$ $\text{days}$. In how many $\text{days}$ would $14$ men complete the same piece of work working $9\, \text{hours}$ daily?

Similar Questions

$A$ can do a piece of work in $12$ days and $B$ in $20$ days. If they together work on it for $5$ days and the remaining work is completed by $C$ in $3$ days, then in how many days can $C$ do the same work alone?

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$A$ and $B$ can complete a piece of work in $15$ days and $10$ days respectively. They contracted to complete the work for $Rs. 30000$. The share of $A$ in the contracted money will be (in $Rs.$)

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