Class 12Chemistry8-2.Carboxylic acids and Their derivativeProperties of Carboxylic Acids and Their Derivatives
MediumWrite a note on electrophilic substitution reactions in the ring of aromatic carboxylic acids.
(N/A) $1$. Aromatic carboxylic acids undergo electrophilic substitution reactions.
$2$. The carboxyl group $(-COOH)$ acts as a deactivating and meta-directing group.
$3$. They do not undergo Friedel-Crafts reactions because the carboxyl group is strongly deactivating and the catalyst (Lewis acid,$AlCl_3$) gets bonded to the carboxyl group.
$4$. Examples:
$(i)$ Nitration of benzoic acid: Benzoic acid reacts with conc. $HNO_3$ and conc. $H_2SO_4$ to form $m$-nitrobenzoic acid.
(ii) Bromination of benzoic acid: Benzoic acid reacts with $Br_2$ in the presence of $FeBr_3$ to form $m$-bromobenzoic acid.
(iii) Sulphonation of benzoic acid: Benzoic acid reacts with $H_2SO_4$ (containing $SO_3$) to form $m$-sulphobenzoic acid.
$2$. The carboxyl group $(-COOH)$ acts as a deactivating and meta-directing group.
$3$. They do not undergo Friedel-Crafts reactions because the carboxyl group is strongly deactivating and the catalyst (Lewis acid,$AlCl_3$) gets bonded to the carboxyl group.
$4$. Examples:
$(i)$ Nitration of benzoic acid: Benzoic acid reacts with conc. $HNO_3$ and conc. $H_2SO_4$ to form $m$-nitrobenzoic acid.
(ii) Bromination of benzoic acid: Benzoic acid reacts with $Br_2$ in the presence of $FeBr_3$ to form $m$-bromobenzoic acid.
(iii) Sulphonation of benzoic acid: Benzoic acid reacts with $H_2SO_4$ (containing $SO_3$) to form $m$-sulphobenzoic acid.
Explore More
Similar Questions
Identify products $A$ and $B$ in the following reaction:
$R-COOR' \xrightarrow[\text{dry ether}]{LiAlH_4} A + B$
$R-COOR' \xrightarrow[\text{dry ether}]{LiAlH_4} A + B$
Ethanoic acid undergoes Hell-Volhard Zelinsky reaction but methanoic acid does not,because of
MediumKCET 2022
View SolutionWhat will be the product $D$ in the following reaction?
$CH_3Cl$ $\xrightarrow{KCN} (A)$ $\xrightarrow{H_3O^+} (B)$ $\xrightarrow{NH_3} (C)$ $\xrightarrow{\Delta} (D)$
$CH_3Cl$ $\xrightarrow{KCN} (A)$ $\xrightarrow{H_3O^+} (B)$ $\xrightarrow{NH_3} (C)$ $\xrightarrow{\Delta} (D)$
Difficult
View SolutionThe increasing order of acidic strength among the following compounds is
$I.$ Benzoic acid
$II.$ $4-$nitrobenzoic acid
$III.$ $3, 4-$dinitrobenzoic acid
$IV.$ $4-$methoxybenzoic acid
$I.$ Benzoic acid
$II.$ $4-$nitrobenzoic acid
$III.$ $3, 4-$dinitrobenzoic acid
$IV.$ $4-$methoxybenzoic acid
In the reaction,$CH_3-COOH$ $\xrightarrow{LiAlH_4} A$ $\xrightarrow{PCl_5} B$ $\xrightarrow{Alc. KOH} C$,the product $C$ is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo