Write a test to differentiate between pentan$-2-$one and pentan$-3-$one.
Pentan$-2-$one contains a $CH_3CO-$ group,therefore it gives a positive iodoform test with $I_2/NaOH$,forming a yellow precipitate of iodoform $(CHI_3)$.
Pentan$-3-$one does not contain a $CH_3CO-$ group,therefore it does not give a positive iodoform test.
Reaction:
$CH_3CH_2CH_2COCH_3 + 3I_2 + 4NaOH \rightarrow CH_3CH_2CH_2COONa + CHI_3 \text{ (yellow ppt)} + 3NaI + 3H_2O$
$CH_3CH_2COCH_2CH_3 + I_2/NaOH \rightarrow \text{No reaction}$
Pentan$-3-$one does not contain a $CH_3CO-$ group,therefore it does not give a positive iodoform test.
Reaction:
$CH_3CH_2CH_2COCH_3 + 3I_2 + 4NaOH \rightarrow CH_3CH_2CH_2COONa + CHI_3 \text{ (yellow ppt)} + 3NaI + 3H_2O$
$CH_3CH_2COCH_2CH_3 + I_2/NaOH \rightarrow \text{No reaction}$
Explore More
Similar Questions
How can propan$-2-$one be converted to tertiary butyl alcohol?
Medium
View SolutionWhat are $X$ and $Y$ in the following reaction sequence?
$Propene$ $\xrightarrow{HBr} A$ $\xrightarrow[Dry \ ether]{Mg} B$ $\xrightarrow[2. H_3O^{+}]{1. X} Y$
$Propene$ $\xrightarrow{HBr} A$ $\xrightarrow[Dry \ ether]{Mg} B$ $\xrightarrow[2. H_3O^{+}]{1. X} Y$
DifficultAP EAMCET 2018
View SolutionThe following reagent converts $C_6H_5COCHO$ to $C_6H_5CHOHCOONa$.
Medium
View SolutionIdentify product $B$ in the following sequence of reactions:
$2 \ CH_3COCH_3$ $\xrightarrow{Ba(OH)_2} A$ $\xrightarrow{\Delta, -H_2O} B$
$2 \ CH_3COCH_3$ $\xrightarrow{Ba(OH)_2} A$ $\xrightarrow{\Delta, -H_2O} B$
The ratio $x / y$ on completion of the above reaction is $.........$.
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo