Write the equation of pressure of an ideal gas in terms of its density.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The pressure $P$ of an ideal gas is given by the kinetic theory of gases as:
$P = \frac{1}{3} \rho v_{rms}^2$
Where:
$P$ is the pressure of the gas,
$\rho$ is the density of the gas,
$v_{rms}$ is the root mean square speed of the gas molecules.
Alternatively,using the ideal gas equation $PV = nRT = \frac{m}{M} RT$,we can write $P = \frac{\rho RT}{M}$,where $M$ is the molar mass and $R$ is the universal gas constant.

Explore More

Similar Questions

An ideal gas occupies a volume of $2\, m^3$ at a pressure of $3\times10^6\, Pa$. The energy of the gas is

$A$ flask contains argon and chlorine in the ratio of $2:1$ by mass. The temperature of the mixture is $27^{\circ} C$. The ratio of average kinetic energies of two gases per molecule is (in $:1$)

The energy of a gas per litre is $300 \ J$. Then its pressure will be:

Difficult
View Solution

If the $rms$ velocity of a gas in a container is doubled,the pressure will .........

The average translational kinetic energy of a hydrogen gas molecule at $NTP$ will be. [Boltzmann's constant $k_B = 1.38 \times 10^{-23} \text{ J/K}$]

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo