Write four solutions for the following equation:
$2x - 12 = 0$

(N/A) Given equation: $2x - 12 = 0$
Step $1$: Simplify the equation to solve for $x$.
$2x = 12$
$x = 6$
Step $2$: Express the equation in the form $ax + by + c = 0$.
$1x + 0y - 6 = 0$
Step $3$: Since the coefficient of $y$ is $0$,the value of $x$ will always be $6$ regardless of the value of $y$. We can choose any four arbitrary values for $y$ to find the corresponding solutions $(x, y)$.
Let $y = 0$,then $x = 6$. Solution: $(6, 0)$
Let $y = 1$,then $x = 6$. Solution: $(6, 1)$
Let $y = 2$,then $x = 6$. Solution: $(6, 2)$
Let $y = 3$,then $x = 6$. Solution: $(6, 3)$
Thus,four solutions are $(6, 0), (6, 1), (6, 2),$ and $(6, 3)$.