Write four solutions for the equation: $2x + y = 7$
(N/A) To find solutions for the equation $2x + y = 7$,we can express $y$ in terms of $x$: $y = 7 - 2x$.
By substituting different values of $x$,we get corresponding values of $y$:
$1$. When $x = 0$,$y = 7 - 2(0) = 7$. Thus,the solution is $(0, 7)$.
$2$. When $x = 1$,$y = 7 - 2(1) = 5$. Thus,the solution is $(1, 5)$.
$3$. When $x = 2$,$y = 7 - 2(2) = 3$. Thus,the solution is $(2, 3)$.
$4$. When $x = 3$,$y = 7 - 2(3) = 1$. Thus,the solution is $(3, 1)$.
By substituting different values of $x$,we get corresponding values of $y$:
$1$. When $x = 0$,$y = 7 - 2(0) = 7$. Thus,the solution is $(0, 7)$.
$2$. When $x = 1$,$y = 7 - 2(1) = 5$. Thus,the solution is $(1, 5)$.
$3$. When $x = 2$,$y = 7 - 2(2) = 3$. Thus,the solution is $(2, 3)$.
$4$. When $x = 3$,$y = 7 - 2(3) = 1$. Thus,the solution is $(3, 1)$.
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