Write Lewis symbols for the following atoms and ions:
$S$ and $S^{2-}$; $Al$ and $Al^{3+}$; $H$ and $H^{-}$

(N/A) $(i)$ $S$ and $S^{2-}$
The number of valence electrons in sulphur is $6$.
The Lewis dot symbol of sulphur $(S)$ is $: \ddot{S} :$.
The dinegative charge infers that there will be two electrons more in addition to the six valence electrons. Hence,the Lewis dot symbol of $S^{2-}$ is $\left[ : \underset{\cdot \cdot}{\ddot{S}} : \right]^{2-}$.
$(ii)$ $Al$ and $Al^{3+}$
The number of valence electrons in aluminium is $3$.
The Lewis dot symbol of aluminium $(Al)$ is $\cdot \underset{\cdot}{A}l \cdot$.
The tripositive charge on a species infers that it has donated its three electrons. Hence,the Lewis dot symbol is $[Al]^{3+}$.
$(iii)$ $H$ and $H^{-}$
The number of valence electrons in hydrogen is $1$.
The Lewis dot symbol of hydrogen $(H)$ is $H \cdot$.
The uninegative charge infers that there will be one electron more in addition to the one valence electron. Hence,the Lewis dot symbol is $\left[ \ddot{H} \right]^{-}$.