Write the coefficient of x^{2} in the followi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given polynomial is $p(x) = x^{3} + 27$.To find the coefficient of $x^{2}$,we can rewrite the polynomial as $p(x) = 1 \cdot x^{3} + 0 \cdot x^

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) The given polynomial is $p(x) = x^{3} + 27$.To find the coefficient of $x^{2}$,we can rewrite the polynomial as $p(x) = 1 \cdot x^{3} + 0 \cdot x^{2} + 0 \cdot x + 27$.Comparing this with the standard form,the term containing $x^{2}$ is $0 \cdot x^{2}$.Therefore,the coefficient of $x^{2}$ is $0$.

Write the coefficient of $x^{2}$ in the following polynomial: $x^{3} + 27$.

Similar Questions

Factorise:
$a^{3}-8 b^{3}-64 c^{3}-24 a b c$

Expand $(a - 2b + 7c)^2$.

If $a+b+c=5$ and $ab+bc+ca=10$,then prove that $a^3+b^3+c^3-3abc=-25$.

Classify the following as linear,quadratic,or cubic polynomial: $4y + 11$.

Factorise $12 x^{3} + 17 x^{2} + 3 x - 2$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module