Write the degree of the following polynomial: $\sqrt{11} t+14$.

(1) The given polynomial is $p(t) = \sqrt{11} t + 14$.
In a polynomial,the degree is defined as the highest power of the variable present in the expression.
Here,the variable is $t$,and its exponent is $1$.
Therefore,the degree of the polynomial $\sqrt{11} t + 14$ is $1$.