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Question

(A) The intensity of radiation $(I)$ is defined as the energy $(E)$ incident per unit area $(A)$ per unit time $(t)$.Mathematically,$I = \frac{E}{A

Vedclass · Accepted Answer

$M^{1} L^{0} T^{-3}$

Vedclass · Answer

(A) The intensity of radiation $(I)$ is defined as the energy $(E)$ incident per unit area $(A)$ per unit time $(t)$.Mathematically,$I = \frac{E}{A 	imes t}$.The dimensional formula for energy $(E)$ is $[M^{1} L^{2} T^{-2}]$.The dimensional formula for area $(A)$ is $[L^{2}]$.The dimensional formula for time $(t)$ is $[T^{1}]$.Substituting these into the formula:$I = \frac{[M^{1} L^{2} T^{-2}]}{[L^{2}] 	imes [T^{1}]}$$I = [M^{1} L^{2-2} T^{-2-1}]$$I = [M^{1} L^{0} T^{-3}]$Therefore,the correct option is $A$.

List $I$	List $II$
$A$. Spring constant	$I$. $(T^{-1})$
$B$. Angular speed	$II$. $(MT^{-2})$
$C$. Angular momentum	$III$. $(ML^2)$
$D$. Moment of inertia	$IV$. $(ML^2T^{-1})$

Write the dimensional formula for the intensity of radiation.

Similar Questions

Given below are two statements :
Statement $(I)$ : Dimensions of specific heat are $\left[L^2 \,T^{-2} \,K^{-1}\right]$.
Statement $(II)$ : Dimensions of gas constant are $\left[ML^2 \,T^{-1} \,K^{-1}\right]$.

The dimensions of $(\mu_0 \varepsilon_0)^{-1/2}$ are

Two quantities $A$ and $B$ are related by the equation $A/B = m$,where $m$ is linear density and $A$ is force. The dimensions of $B$ are equivalent to which of the following?

Match List $I$ with List $II$:
List $I$ List $II$
$A$. Spring constant $I$. $(T^{-1})$
$B$. Angular speed $II$. $(MT^{-2})$
$C$. Angular momentum $III$. $(ML^2)$
$D$. Moment of inertia $IV$. $(ML^2T^{-1})$

Choose the correct answer from the options given below:

Dimensions of which pair are the same? Identify the pair.

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