Write the formula for the capacitance of a capacitor having a dielectric constant $K = 2$.
(N/A) The capacitance of a parallel plate capacitor in a vacuum is given by $C_0 = \frac{\epsilon_0 A}{d}$,where $\epsilon_0$ is the permittivity of free space,$A$ is the area of the plates,and $d$ is the distance between them.
When a dielectric material with dielectric constant $K$ is introduced between the plates,the new capacitance $C$ becomes $C = K C_0$.
Given that $K = 2$,the formula for the capacitance becomes $C = 2 C_0 = \frac{2 \epsilon_0 A}{d}$.
When a dielectric material with dielectric constant $K$ is introduced between the plates,the new capacitance $C$ becomes $C = K C_0$.
Given that $K = 2$,the formula for the capacitance becomes $C = 2 C_0 = \frac{2 \epsilon_0 A}{d}$.
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