Write the formula to find the magnitude of the gravitational force between the Earth and an object on the surface of the Earth.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Let $M_E$ be the mass of the Earth and $m$ be the mass of an object on its surface. If $R$ is the radius of the Earth,then according to the universal law of gravitation,the gravitational force $(F)$ acting between the Earth and the object is given by the relation:
$F = \frac{G M_E m}{R^2}$
Where:
$G$ is the universal gravitational constant,
$M_E$ is the mass of the Earth,
$m$ is the mass of the object,
$R$ is the distance between the center of the Earth and the object (which is equal to the radius of the Earth).

Explore More

Similar Questions

What do we call the gravitational force between the earth and an object?

What are the differences between the mass of an object and its weight?

Gravitational force on the surface of the moon is only $\frac{1}{6}$ as strong as the gravitational force on the earth. What is the weight in newtons of a $10\, kg$ object on the moon and on the earth?

You have a bag of cotton and an iron bar,each indicating a mass of $100\, kg$ when measured on a weighing machine. In reality,one is heavier than the other. Can you say which one is heavier and why?

Amit buys a few grams of gold at the poles as per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the weight of gold bought? If not,why? [Hint: The value of $g$ is greater at the poles than at the equator.]

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo