Write the chemical formulae for the following substances and calculate the molecular mass for each one of them:
$(a)$ Caustic potash
$(b)$ Baking soda
$(c)$ Limestone
$(d)$ Caustic soda
$(e)$ Ethanol
$(f)$ Common salt
$(a)$ Caustic potash
$(b)$ Baking soda
$(c)$ Limestone
$(d)$ Caustic soda
$(e)$ Ethanol
$(f)$ Common salt
(N/A) Caustic potash: $KOH$
Molecular mass: $39 + 16 + 1 = 56 \, g \, mol^{-1}$
$(b)$ Baking soda: $NaHCO_3$
Molecular mass: $23 + 1 + 12 + (3 \times 16) = 84 \, g \, mol^{-1}$
$(c)$ Limestone: $CaCO_3$
Molecular mass: $40 + 12 + (3 \times 16) = 100 \, g \, mol^{-1}$
$(d)$ Caustic soda: $NaOH$
Molecular mass: $23 + 16 + 1 = 40 \, g \, mol^{-1}$
$(e)$ Ethanol: $C_2H_5OH$
Molecular mass: $(2 \times 12) + (6 \times 1) + 16 = 46 \, g \, mol^{-1}$
$(f)$ Common salt: $NaCl$
Molecular mass: $23 + 35.5 = 58.5 \, g \, mol^{-1}$
Molecular mass: $39 + 16 + 1 = 56 \, g \, mol^{-1}$
$(b)$ Baking soda: $NaHCO_3$
Molecular mass: $23 + 1 + 12 + (3 \times 16) = 84 \, g \, mol^{-1}$
$(c)$ Limestone: $CaCO_3$
Molecular mass: $40 + 12 + (3 \times 16) = 100 \, g \, mol^{-1}$
$(d)$ Caustic soda: $NaOH$
Molecular mass: $23 + 16 + 1 = 40 \, g \, mol^{-1}$
$(e)$ Ethanol: $C_2H_5OH$
Molecular mass: $(2 \times 12) + (6 \times 1) + 16 = 46 \, g \, mol^{-1}$
$(f)$ Common salt: $NaCl$
Molecular mass: $23 + 35.5 = 58.5 \, g \, mol^{-1}$
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