Write the measures of the sides of $\Delta XYZ$ in ascending order,given that $\angle X = 80^{\circ}$ and $\angle Y = 30^{\circ}$.
(A) In $\Delta XYZ$,the sum of angles is $180^{\circ}$.
Therefore,$\angle Z = 180^{\circ} - (80^{\circ} + 30^{\circ}) = 180^{\circ} - 110^{\circ} = 70^{\circ}$.
The angles in ascending order are $\angle Y (30^{\circ}) < \angle Z (70^{\circ}) < \angle X (80^{\circ})$.
Since the side opposite to the smaller angle is smaller,the sides in ascending order are $XZ < XY < YZ$.
Therefore,$\angle Z = 180^{\circ} - (80^{\circ} + 30^{\circ}) = 180^{\circ} - 110^{\circ} = 70^{\circ}$.
The angles in ascending order are $\angle Y (30^{\circ}) < \angle Z (70^{\circ}) < \angle X (80^{\circ})$.
Since the side opposite to the smaller angle is smaller,the sides in ascending order are $XZ < XY < YZ$.
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