Yellow light emitted from a sodium lamp has a wavelength $(\lambda)$ of $580 \,nm$. Calculate the frequency $(v)$ and wave number $(\bar{v})$ of the yellow light.

(N/A) Given:
$\lambda = 580 \,nm = 580 \times 10^{-9} \,m$
$c = 3 \times 10^{8} \,m/s$
$1$. Frequency $(v)$:
Using the relation $v = \frac{c}{\lambda}$,
$v = \frac{3 \times 10^{8} \,m/s}{580 \times 10^{-9} \,m} = 5.17 \times 10^{14} \,s^{-1}$
$2$. Wave number $(\bar{v})$:
Using the relation $\bar{v} = \frac{1}{\lambda}$,
$\bar{v} = \frac{1}{580 \times 10^{-9} \,m} = 1.72 \times 10^{6} \,m^{-1}$
Thus,the frequency is $5.17 \times 10^{14} \,s^{-1}$ and the wave number is $1.72 \times 10^{6} \,m^{-1}$.