₹ 600 is divided among A, B and C. If frac{2} | vedclass

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Question

(A) Let the equal value be $x$.Then,$\frac{2}{5} A + 40 = x \implies A = \frac{5}{2}(x - 40)$.$\frac{2}{7} B + 20 = x \implies B = \frac{7}{2}(x - 20)

Vedclass · Accepted Answer

$150$

Vedclass · Answer

(A) Let the equal value be $x$.Then,$\frac{2}{5} A + 40 = x \implies A = \frac{5}{2}(x - 40)$.$\frac{2}{7} B + 20 = x \implies B = \frac{7}{2}(x - 20)$.$\frac{9}{17} C + 10 = x \implies C = \frac{17}{9}(x - 10)$.Since $A + B + C = 600$,we have:$\frac{5}{2}(x - 40) + \frac{7}{2}(x - 20) + \frac{17}{9}(x - 10) = 600$.$\frac{5x}{2} - 100 + \frac{7x}{2} - 70 + \frac{17x}{9} - \frac{170}{9} = 600$.$6x - 170 + \frac{17x - 170}{9} = 600$.$6x + \frac{17x}{9} = 770 + \frac{170}{9}$.$\frac{54x + 17x}{9} = \frac{6930 + 170}{9}$.$71x = 7100 \implies x = 100$.Thus,$A$'s share = $\frac{5}{2}(100 - 40) = \frac{5}{2}(60) = 150$.

₹ $600$ is divided among $A, B$ and $C$. If $\frac{2}{5}$ of $A$'s share plus ₹ $40$,$\frac{2}{7}$ of $B$'s share plus ₹ $20$,and $\frac{9}{17}$ of $C$'s share plus ₹ $10$ are all equal,then $A$'s share is (in ₹):

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