A DNA fragment contains 120 adenine and 120 c | vedclass

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(C) According to Chargaff's rule for $DNA$,the amount of adenine $(A)$ is equal to the amount of thymine $(T)$,and the amount of cytosine $(C)$ is equ

Vedclass · Accepted Answer

$480$

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(C) According to Chargaff's rule for $DNA$,the amount of adenine $(A)$ is equal to the amount of thymine $(T)$,and the amount of cytosine $(C)$ is equal to the amount of guanine $(G)$.Given: $A = 120$,therefore $T = 120$.Given: $C = 120$,therefore $G = 120$.The total number of nitrogenous bases is $A + T + C + G = 120 + 120 + 120 + 120 = 480$.Since each nitrogenous base is attached to a sugar and a phosphate group to form a nucleotide,the total number of nucleotides in the $DNA$ fragment is equal to the total number of nitrogenous bases,which is $480$.

$A$ $DNA$ fragment contains $120$ adenine and $120$ cytosine bases. What is the total number of nucleotides present in this fragment?

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