CrO _4^{2-} underset{ pH = y }{stackrel{ pH = | vedclass

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(A) The interconversion between chromate $(CrO_4^{2-})$ and dichromate $(Cr_2O_7^{2-})$ ions is dependent on the $pH$ of the solution.
In an acidic m

Vedclass · Accepted Answer

$6, 8$

Vedclass · Answer

(A) The interconversion between chromate $(CrO_4^{2-})$ and dichromate $(Cr_2O_7^{2-})$ ions is dependent on the $pH$ of the solution. In an acidic medium $(pH < 7)$,the chromate ion ($CrO_4^{2-}$,yellow) is converted into the dichromate ion ($Cr_2O_7^{2-}$,orange) according to the reaction: $2CrO_4^{2-} + 2H^+ \rightarrow Cr_2O_7^{2-} + H_2O$. In a basic medium $(pH > 7)$,the dichromate ion $(Cr_2O_7^{2-})$ is converted back into the chromate ion $(CrO_4^{2-})$ according to the reaction: $Cr_2O_7^{2-} + 2OH^- \rightarrow 2CrO_4^{2-} + H_2O$. Given the reaction $CrO _4^{2-} \underset{ pH = y }{\stackrel{ pH = x }{\longleftrightarrow}} Cr _2 O _7^{2-}$,$x$ represents the acidic condition $(pH < 7)$ and $y$ represents the basic condition $(pH > 7)$. Comparing the given options,option $A$ $(6, 8)$ correctly represents an acidic $pH$ $(6)$ for the forward reaction and a basic $pH$ $(8)$ for the reverse reaction.

$CrO _4^{2-} \underset{ pH = y }{\stackrel{ pH = x }{\longleftrightarrow}} Cr _2 O _7^{2-}$
$pH$ values of $x$ and $y$ are respectively

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$CrO _4^{2-} \underset{ pH = y }{\stackrel{ pH = x }{\longleftrightarrow}} Cr _2 O _7^{2-}$ $pH$ values of $x$ and $y$ are respectively