(C) Number of moles of urea $= \frac{\text{Number of molecules}}{N_A} = \frac{6.02 \times 10^{20}}{6.02 \times 10^{23}} = 10^{-3} \ mol$. Molarity $(M

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(C) Number of moles of urea $= \frac{\text{Number of molecules}}{N_A} = \frac{6.02 \times 10^{20}}{6.02 \times 10^{23}} = 10^{-3} \ mol$. Molarity $(M) = \frac{\text{moles of solute}}{\text{volume of solution in } L} = \frac{10^{-3} \ mol}{200 \ mL \times 10^{-3} \ L/mL} = \frac{10^{-3}}{0.2} = 0.005 \ M$.

Class 11 Chemistry Some Basic Concepts of Chemistry The mole concept

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$6.02 \times 10^{20}$ molecules of urea are present in $200 \ mL$ of its solution. The concentration of urea solution is .............. $M$

A
$0.001$
B
$0.01$
C
$0.005$
D
$0.10$

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Some Basic Concepts of Chemistry

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The mole concept

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$6.02 \times 10^{20}$ molecules of urea are present in $200 \ mL$ of its solution. The concentration of urea solution is .............. $M$

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The number of $H$ atoms in $27 \ g$ of water is .........

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