P_4O_{10} has short and long P-O bonds. The n | vedclass

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(D) The structure of $P_4O_{10}$ consists of a $P_4$ tetrahedron where each $P$ atom is bonded to three bridging oxygen atoms ($P-O-P$ bonds) and one

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$4$

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(D) The structure of $P_4O_{10}$ consists of a $P_4$ tetrahedron where each $P$ atom is bonded to three bridging oxygen atoms ($P-O-P$ bonds) and one terminal oxygen atom via a double bond $(P=O)$.There are $4$ such terminal $P=O$ bonds,which are shorter than the bridging $P-O$ bonds.Therefore,the number of short $P=O$ bonds is $4$.

$P_4O_{10}$ has short and long $P-O$ bonds. The number of short $P=O$ bonds in this compound is

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