Vinylcyclopentane xrightarrow{HCl} Major prod | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction proceeds via the formation of a carbocation intermediate. $1$. Protonation of the alkene gives a secondary carbocation on the side ch

Vedclass · Accepted Answer

$1-$chloro$-1-$methylcyclohexane

Vedclass · Answer

(A) The reaction proceeds via the formation of a carbocation intermediate. $1$. Protonation of the alkene gives a secondary carbocation on the side chain. $2$. The five-membered ring undergoes ring expansion to form a more stable six-membered ring carbocation. $3$. $A$ $1,2$-hydride shift occurs to form a more stable tertiary carbocation. $4$. Finally,the chloride ion attacks the tertiary carbocation to form $1$-chloro-$1$-methylcyclohexane.

Vinylcyclopentane $\xrightarrow{HCl}$ Major product is

Similar Questions

$CH_3-CH_2-CH_2-Cl$ $\xrightarrow{KOH_{(aq)}} X$ $\xrightarrow{H^{+}/\Delta} Y$ $\xrightarrow{Cl_2/H_2O} Z$ (Major); $Z$ is

The elimination reaction of $2-$bromopentane to form pent$-2-$ene involves:
$a$. $\beta-$Elimination reaction
$b$. Following Zaitsev rule
$c$. Dehydrohalogenation reaction
$d$. Dehydration reaction

What is the order of ease of dehydrohalogenation of alkyl halides?

In the reaction of $1$-vinyl-$-2$-bromoethylbenzene with $HBr$,the major product is:

Gem dihalide on hydrolysis gives:

Vedclass Test Series

Exam Paper Generator

Online Exam Module