R-CONH_2 xrightarrow[Delta]{KOBr} R-NH_2. The | vedclass

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Question

(B) The reaction $R-CONH_2 \xrightarrow[\Delta]{KOBr} R-NH_2$ is the $Hoffmann$ bromamide degradation reaction.In this reaction,an amide is converted

Vedclass · Accepted Answer

It is optically active and has one carbon less than the reactant.

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(B) The reaction $R-CONH_2 \xrightarrow[\Delta]{KOBr} R-NH_2$ is the $Hoffmann$ bromamide degradation reaction.In this reaction,an amide is converted into a primary amine with one carbon atom less than the original amide.Since the product is a primary amine $(R-NH_2)$,it will give the Carbylamine test (a characteristic test for primary amines).If the $R$ group is chiral,the product will be optically active.However,the most general and defining characteristic of this reaction is the loss of one carbon atom from the amide group to form the amine.

$R-CONH_2 \xrightarrow[\Delta]{KOBr} R-NH_2$. The correct statement about the product is:

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