A sample of [Cu(NH_3)_4]SO_4 contains 2.4 tim | vedclass

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(B) The chemical formula $[Cu(NH_3)_4]SO_4$ indicates that $1 	ext{ mole}$ of the compound contains $4 	ext{ moles}$ of ammonia $(NH_3)$ molecules.N

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(B) The chemical formula $[Cu(NH_3)_4]SO_4$ indicates that $1 	ext{ mole}$ of the compound contains $4 	ext{ moles}$ of ammonia $(NH_3)$ molecules.Number of moles of $NH_3$ molecules = $\frac{	ext{Total number of molecules}}{	ext{Avogadro's number}} = \frac{2.4 	imes 10^{24}}{6.022 	imes 10^{23}} \approx 4 	ext{ moles}$.Since $4 	ext{ moles}$ of $NH_3$ are present in $1 	ext{ mole}$ of $[Cu(NH_3)_4]SO_4$,the number of moles of $[Cu(NH_3)_4]SO_4$ is $\frac{4}{4} = 1 	ext{ mole}$.

$A$ sample of $[Cu(NH_3)_4]SO_4$ contains $2.4 \times 10^{24}$ ammonia molecules. The moles of $[Cu(NH_3)_4]SO_4$ in the given sample will be:

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