The total number of protons in 10 g of calci | vedclass

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(C) The molar mass of $CaCO_3 = 40 + 12 + (3 	imes 16) = 100 \ g/mol$. Number of moles in $10 \ g$ of $CaCO_3 = \frac{10 \ g}{100 \ g/mol} = 0.1 \ mo

Vedclass · Accepted Answer

$3.0115 	imes 10^{24}$

Vedclass · Answer

(C) The molar mass of $CaCO_3 = 40 + 12 + (3 	imes 16) = 100 \ g/mol$. Number of moles in $10 \ g$ of $CaCO_3 = \frac{10 \ g}{100 \ g/mol} = 0.1 \ mol$. Number of molecules $= 0.1 	imes 6.023 	imes 10^{23} = 6.023 	imes 10^{22}$ molecules. Number of protons in one molecule of $CaCO_3$ $(Ca=20, C=6, O=8)$: $20 + 6 + (3 	imes 8) = 50$ protons. Total number of protons $= 50 	imes 6.023 	imes 10^{22} = 3.0115 	imes 10^{24}$.

The total number of protons in $10 \ g$ of calcium carbonate is $(N_0 = 6.023 \times 10^{23})$

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