CH_3CH_2OH xrightarrow{Red P + I_2} (A) xrig | vedclass

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(D) Step $1$: $CH_3CH_2OH + Red \ P + I_2 \rightarrow CH_3CH_2I$ (Compound $A$ is ethyl iodide).Step $2$: $CH_3CH_2I + Mg \xrightarrow{Ether} CH_3CH_2

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$n-$ Propyl alcohol

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(D) Step $1$: $CH_3CH_2OH + Red \ P + I_2 \rightarrow CH_3CH_2I$ (Compound $A$ is ethyl iodide).Step $2$: $CH_3CH_2I + Mg \xrightarrow{Ether} CH_3CH_2MgI$ (Compound $B$ is ethyl magnesium iodide).Step $3$: $CH_3CH_2MgI + HCHO \rightarrow CH_3CH_2CH_2OMgI$ (Compound $C$ is an adduct).Step $4$: $CH_3CH_2CH_2OMgI + H_2O \rightarrow CH_3CH_2CH_2OH + Mg(OH)I$ (Compound $D$ is $n-$ propyl alcohol).

$CH_3CH_2OH$ $\xrightarrow{Red \ P + I_2} (A)$ $\xrightarrow[Ether]{Mg} (B)$ $\xrightarrow{HCHO} (C)$ $\xrightarrow{H_2O} (D)$
The compound $(D)$ is

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$CH_3CH_2OH$ $\xrightarrow{Red \ P + I_2} (A)$ $\xrightarrow[Ether]{Mg} (B)$ $\xrightarrow{HCHO} (C)$ $\xrightarrow{H_2O} (D)$The compound $(D)$ is